c++實現版本層次遍歷功能
采用隊列實現,BFS,功能:BFS層次遍歷打印、按照節點將BFS序列化成一個字符。
#include <iostream> #include <string> #include <queue> using namespace std; struct TreeNode { int val; TreeNode* left; TreeNode* right; TreeNode(int val) : val(val), left(nullptr), right(nullptr) {} }; //迭代打印層次遍歷 void BFSTraverse(TreeNode* root) { queue<TreeNode*> nodeQueue; nodeQueue.push(root);//先把第一個先放到列表裡面 while (!nodeQueue.empty()) { int sz = nodeQueue.size();//這個是為瞭一層一層的數值進行處理 for (int i = 0; i < sz; i++) { //那就取出那個節點進行處理 TreeNode* node = nodeQueue.front(); cout << node->val << ", "; nodeQueue.pop(); if (node->left) { nodeQueue.push(node->left); } if (node->right) { nodeQueue.push(node->right); } } } } //按照節點進行序列化成一個字符串 string serialByBFS(TreeNode* root) { if (root == nullptr) return "#!"; queue<TreeNode*> nodeQueue; nodeQueue.push(root); string res; while (!nodeQueue.empty()) { int sz = nodeQueue.size(); for (int i = 0; i < sz; i++) { TreeNode* node = nodeQueue.front(); nodeQueue.pop(); if (node) { res = res + std::to_string(node->val) + '!'; nodeQueue.push(node->left); nodeQueue.push(node->right); } else { res = res + "#!"; } } } return res; } int main3() { TreeNode* head = new TreeNode(5); head->left = new TreeNode(3); head->right = new TreeNode(8); head->left->left = new TreeNode(1); head->left->right = new TreeNode(2); head->right->left = new TreeNode(4); head->right->right = new TreeNode(5); head->right->left->left = new TreeNode(6); head->right->right->left = new TreeNode(9); head->right->right->right = new TreeNode(11); cout << "traverse1:"; BFSTraverse(head); cout << "\nserial binary:"; string res = serialByBFS(head); cout << res << endl; return 0; }
ps:下面看下C++層次遍歷
/* * description:層次遍歷 * writeby: nick * date: 2012-10-22 23:56 */ #include <iostream> #include <queue> using namespace std; struct node { int item; node *l, *r; node(int n) { item=n; l=0; r=0; } }; typedef node *link; void traverse(link h, void visit(link)) { queue<link> q; q.push(h); while(!q.empty()) { h = q.front(); q.pop(); visit(h); if(h->l != 0) q.push(h->l); if(h->r !=0) q.push(h->r); } } void visit(link p) { cout << p->item << " "; } int main() { link root = new node(4); root->l = new node(5); root->r = new node(6); root->l->l = new node(7); root->l->r = new node(8); cout << "中文"; traverse(root, visit); return 0; }
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