mysql中TIMESTAMPDIFF案例詳解

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1.  Syntax

TIMESTAMPDIFF(unit,begin,end); 根據單位返回時間差,對於傳入的begin和end不需要相同的數據結構,可以存在一個為Date一個DateTime

2. Unit

支持的單位有

  • MICROSECOND
  • SECOND
  • MINUTE
  • HOUR
  • DAY
  • WEEK
  • MONTH
  • QUARTER
  • YEAR

3. Example

下面這個例子是對於TIMESTAMPDIFF最基本的用法，

  • 3.1 求 2017-01-01 – 2017-02-01 之間有幾個月
SELECT TIMESTAMPDIFF(MONTH, '2017-01-01', '2017-02-01') as  result;

+--------+
| result |
+--------+
| 1 |
+--------+
1 row in set (0.00 sec)
  • 3.2 求 2017-01-01 – 2017-02-01 之間有幾天
SELECT TIMESTAMPDIFF(DAY, '2017-01-01', '2017-02-01') as  result;

+--------+
| result |
+--------+
| 31 |
+--------+
1 row in set (0.00 sec)
  •  3.3 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:00 之間有幾分鐘
SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:00') result;

+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)
  •  3.4 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:33 之間有幾分鐘
SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;

+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)
  •  3.5 對於DAY， MINUTE進行計算DIFF時，會直接將相對應的DAY，MINUTE相減

  • 3.6 對於 SECOND 會怎樣計算呢
SELECT TIMESTAMPDIFF(SECOND, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;

55 * 60 + 33 = 3333
+--------+
| result |
+--------+
|   3333 |
+--------+
1 row in set (0.00 sec)
  • 3.7 如何求數據庫中兩個date字段的diff
    • 3.7.1  建表 
      CREATE TABLE demo (id INT AUTO_INCREMENT PRIMARY KEY, start_time DATE NOT NULL, end_time DATE NOT NULL);
Query OK, 0 rows affected (0.10 sec)

    • 3.7.2  添加數據 
      INSERT INTO demo(start_time, end_time)
VALUES('1983-01-01', '1990-01-01'),
('1983-01-01', '1989-06-06'),
('1983-01-01', '1985-03-02'),
('1983-01-01', '1992-05-05'),
('1983-01-01 11:12:11', '1995-12-01');

    • 3.7.3 直接query數據 
      select * from demo;
+----+------------+------------+
| id | start_time | end_time |
+----+------------+------------+
| 1 | 1983-01-01 | 1990-01-01 |
| 2 | 1983-01-01 | 1989-06-06 |
| 3 | 1983-01-01 | 1985-03-02 |
| 4 | 1983-01-01 | 1992-05-05 |
| 5 | 1983-01-01 | 1995-12-01 |
+----+------------+------------+
5 rows in set (0.00 sec)

    • 3.7.4 計算duration 
      select *, TIMESTAMPDIFF(YEAR, start_time, end_time) as duration from demo;

+----+------------+------------+----------+
| id | start_time | end_time | duration |
+----+------------+------------+----------+
| 1 | 1983-01-01 | 1990-01-01 | 7 |
| 2 | 1983-01-01 | 1989-06-06 | 6 |
| 3 | 1983-01-01 | 1985-03-02 | 2 |
| 4 | 1983-01-01 | 1992-05-05 | 9 |
| 5 | 1983-01-01 | 1995-12-01 | 12 |
+----+------------+------------+----------+
5 rows in set (0.00 sec)

    • 3.7.5 其他應用 
      select *, if(TIMESTAMPDIFF(YEAR, end_time, CURRENT_TIMESTAMP())< 26 ,'< 26','>= 26') as result from demo;

+----+------------+------------+--------+
| id | start_time | end_time | result |
+----+------------+------------+--------+
| 1 | 1983-01-01 | 1990-01-01 | >= 26 |
| 2 | 1983-01-01 | 1989-06-06 | >= 26 |
| 3 | 1983-01-01 | 1985-03-02 | >= 26 |
| 4 | 1983-01-01 | 1992-05-05 | < 26 |
| 5 | 1983-01-01 | 1995-12-01 | < 26 |
+----+------------+------------+--------+
5 rows in set (0.00 sec)

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