C++實現數據結構的順序表詳解
前言:
hello,大傢好,這篇文章博主來分享一下C++實現數據結構中的順序表的代碼。希望對大傢有所幫助。
在博主之前的文章中,已經詳細地寫過順序表,讀者可以點擊查看C語言如何建立鏈表並實現增刪查改,在之前的文章中,是用C語言來實現的,這篇文章中,我們用C++來實現。
代碼
1.SeqList.h
#ifndef SEQLIST_H #define SEQLIST_H #include<iostream> using namespace std; template<class T,int MAXSIZE> class SeqList { T data[MAXSIZE]; int length; public: SeqList(); SeqList(T a[],int n); ~SeqList(); int ListLength(); T Get(int pos); int Locate(T item); void SeqPrint(); void Insert(int i, T item); T Delete(int i); }; #endif
2.SeqList.cpp
#define _CRT_SECURE_NO_WARNINGS 1 #include"SeqList.h" template<class T, int MAXSIZE> SeqList<T,MAXSIZE>::SeqList() { length = 0; } template<class T, int MAXSIZE> SeqList<T, MAXSIZE>::SeqList(T a[], int n) { if (n < MAXSIZE) { length = n; for (int i = 0; i < n; i++) { data[i] = a[i]; } } else { cerr << "您的數據已經超過范圍,系統無法繼續工作" << endl; exit(-1); } } template<class T, int MAXSIZE> SeqList<T, MAXSIZE>::~SeqList() { } template<class T, int MAXSIZE> int SeqList<T, MAXSIZE>::ListLength() { return length; } template<class T, int MAXSIZE> T SeqList<T, MAXSIZE>::Get(int pos) { if (pos > length || pos < 0) { cerr << "您要查找的位置不存在,系統無法繼續為您服務" << endl; exit(-1); } else { return data[pos - 1]; } } template<class T, int MAXSIZE> int SeqList<T, MAXSIZE>::Locate(T item) { for (int i = 0; i < length; i++) { if (data[i] == item) return i + 1; } return -1; } template<class T, int MAXSIZE> void SeqList<T, MAXSIZE>::SeqPrint() { for (int i = 0; i < length; i++) { cout << data[i] << " "; } cout << endl; } template<class T, int MAXSIZE> void SeqList<T, MAXSIZE>::Insert(int i, T item) { if (length < MAXSIZE) { for (int j = length - 1; j>=i - 1; j--) { data[j + 1] = data[j]; } data[i - 1] = item; length++; } else { cerr << "抱歉,當前已經達到系統最大的儲存,無法為您插入" << endl; exit(-1); } } template<class T, int MAXSIZE> T SeqList<T, MAXSIZE>::Delete(int i) { if (length == 0) { cerr << "當前無可刪除元素" << endl; exit(-1); } if (i<1 || i>length) { cerr << "該位置非法" << endl; exit(-1); } T x = data[i - 1]; for (int j = i; j < length; j++) { data[j - 1] = data[j]; } length--; return x; }
3.test.cpp
#define _CRT_SECURE_NO_WARNINGS 1 #include"SeqList.cpp" #include<iostream> using namespace std; void menu() { cout << "|------------------------------------|" << endl; cout << "|----------- 歡迎來到順序表 ---------|" << endl; cout << "|---------------1.插入---------------|" << endl; cout << "|---------------2.刪除---------------|" << endl; cout << "|---------------3.求長---------------|" << endl; cout << "|---------------4.取值---------------|" << endl; cout << "|---------------5.定位---------------|" << endl; cout << "|---------------6.打印---------------|" << endl; cout << "|---------------0.退出---------------|" << endl; cout << "|------------------------------------|" << endl; } int main() { int *a; int n; cout << "請輸入您要構造的順序表的長度" << endl; cin >> n; a = new int[n]; cout << "請輸入該順序表中的每一個元素" << endl; for (int i = 0; i < n; i++) { cin >> a[i]; } SeqList<int, 20>seq(a, n); cout << "現在開始我們的程序之旅" << endl; int input=0; do { menu(); cout << "輸入您要進行的操作的編號" << endl; cin >> input; switch (input) { case 1: cout << "請輸入您要插入的位置和數值" << endl; int pos; int value; cin >> pos; cin >> value; seq.Insert(pos,value); break; case 2: cout << "請輸入您要刪除的位置" << endl; int pos1; cin >> pos1; cout << "您刪除的元素的值為:"; cout << seq.Delete(pos1) << endl; break; case 3: cout << "您的順序表當前的長度為:" << seq.ListLength() << endl; break; case 4: cout << "請輸入您要查找的位置" << endl; int pos2; cin >> pos2; cout << "您查找的元素的值為:"; cout << seq.Get(pos2) << endl;; break; case 5: cout << "請輸入您要查找的元素" << endl; int item; cin >> item; cout << "您查找的元素的位置為:"; cout << seq.Locate(item) << endl;; break; case 6: cout << "當前順序表如下:" << endl; seq.SeqPrint(); break; case 0: cout << "程序退出,感謝使用" << endl; exit(-1); break; default : cout << "您的輸入有誤,請重新選擇" << endl; } } while (input); return 0; }
總結
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