python 獲取毫秒級時間問題的解決
根據網上的一些說法,
在python裡獲取ms級系統時間可以通過以下方式獲取:
import datetime print(datetime.datetime.now().microsecond)
但通過以下代碼測試,發現返回的並不是ms的值,而是us的值:
import datetime def getTime_ms(): return (datetime.datetime.now().hour*3600 +\ datetime.datetime.now().minute*60+\ datetime.datetime.now().second )*1000+\ datetime.datetime.now().microsecond/1000 def timetime(): t = getTime_ms() while getTime_ms() - t < 500: pass a = getTime_ms() print(t, a, a- t) if __name__ == '__main__': from timeit import timeit t = timeit('timetime()', 'from __main__ import timetime', number=1) print(t)
打印結果
(35460614, 35461114, 500) 0.499531984329
上面實驗不太直觀,換一個直觀點的:
def timetime(): t1 = datetime.datetime.now() while 1: t2 = datetime.datetime.now() if (t2 - t1).microseconds >= 1: print(t2,t2.microsecond,t1,t1.microsecond,(t2-t1).seconds) break if __name__ == '__main__': from timeit import timeit t = timeit('timetime()', 'from __main__ import timetime', number=1) print(t) #print (datetime.datetime.now())
輸出
(datetime.datetime(2019, 4, 3, 10, 6, 20, 461882), 461882, datetime.datetime(2019, 4, 3, 10, 6, 20, 461863), 461863, 0) 7.10487365723e-05
def timetime(): t1 = datetime.datetime.now() while 1: t2 = datetime.datetime.now() if (t2 - t1).microseconds >= 1000: print(t2,t2.microsecond,t1,t1.microsecond,(t2-t1).seconds) break if __name__ == '__main__': from timeit import timeit t = timeit('timetime()', 'from __main__ import timetime', number=1) print(t) #print (datetime.datetime.now())
輸出
(datetime.datetime(2019, 4, 3, 10, 13, 52, 76548), 76548, datetime.datetime(2019, 4, 3, 10, 13, 52, 75547), 75547, 0) 0.00104904174805
補充:Python datetime去除毫秒 返回當前時間
datetime模塊返回當前時間
import datetime if __name__ == '__main__': a = datetime.datetime.now().replace(microsecond=0) print(a, type(a))
運算結果:
2020-05-22 12:13:42 <class ‘datetime.datetime’> Process finished with exit code 0
以上為個人經驗,希望能給大傢一個參考,也希望大傢多多支持WalkonNet。如有錯誤或未考慮完全的地方,望不吝賜教。
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