Java實戰練習之撲克牌魔術
前言
用到瞭Scanner,for循環,if-else語句,集合,線程的Thread.sleep()方法
話不多說,直接上代碼
代碼
import java.util.ArrayList; import java.util.Collections; import java.util.Scanner; public class CardMagic { public static void main(String[] args) { //1.準備54張牌 //新建一個集合存儲54張牌並打亂順序 ArrayList<String> pokers = new ArrayList<>(); //直接定義兩個數組並賦值,一個存四種花色,一個存13張牌的值(3,4,5,6,7,8,9,10,J,Q,K,A,2) String[] kind = {"♥","♠","♦","♣"}; String[] number = {"3","4","5","6","7","8","9","10","J","Q","K","A","2"}; //先存大王小王到pokers集合中 pokers.add("大王"); pokers.add("小王"); //組裝兩個集合的數據,生成帶花色的52張牌(可以用普通for循環,也可以用增強for循環foreach) for (int i = 0; i < kind.length; i+ +) { for (int j = 0; j < 13; j++) { pokers.add(kind[i]+number[j]); } } System.out.println("這裡有54張牌:"+pokers);//順序打印 //洗牌--打亂pokers集合裡的元素順序 Collections.shuffle(pokers);//打亂順序 //再新建一個集合,用來存儲隨機拿出的21張牌(偽隨機:其實是拿出前21張牌,但是pokers集合是隨機打亂順序的,所以每次運行程序,拿出的前21張牌也就不一樣且亂序瞭) ArrayList<String> list21 = new ArrayList<>(); for (int i = 0; i < 21; i++) { list21.add(pokers.get(i)); } //打印出這21張牌 System.out.println("隨機取出21張撲克牌並打亂順序:"); System.out.println(list21); System.out.println("請選擇任意一張撲克牌,並記住它。【輸入小寫字母'y'繼續,輸入其他任意字符結束遊戲!】"); Scanner scanner1 = new Scanner(System.in); if (scanner1.nextLine().equals("y")){ System.out.println("系統將這21張撲克牌均分為3疊,請等待..."); try { Thread.sleep(3000); } catch (InterruptedException e) { e.printStackTrace(); } }else { System.exit(-1); } //定義3個集合,每個集合存儲7張牌 ArrayList<String> card1 = new ArrayList<>(); ArrayList<String> card2 = new ArrayList<>(); ArrayList<String> card3 = new ArrayList<>(); for (int i = 0; i < 7; i++) { card1.add(list21.get(i)); } for (int i = 7; i < 14; i++) { card2.add(list21.get(i)); } for (int i = 14; i < 21; i++) { card3.add(list21.get(i)); } System.out.println("第1疊:"+card1); System.out.println("第2疊:"+card2); System.out.println("第3疊:"+card3); //判斷輸入 try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } Scanner scanner2 = new Scanner(System.in); System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數字1;如果在第2疊請輸入數字2;如果在第3疊請輸入數字3"); System.out.println("請輸入:"); //新建3個數組,分3次重新存重新按指定規則排序的21張牌 ArrayList<String> list21New1 = new ArrayList<>(); int a = scanner2.nextInt(); if (a==1){ for (int i = 0; i < 7; i++) { list21New1.add(card2.get(i)); } for (int i = 0; i < 7; i++) { list21New1.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New1.add(card3.get(i)); } }else if (a==2){ for (int i = 0; i < 7; i++) { list21New1.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New1.add(card2.get(i)); } for (int i = 0; i < 7; i++) { list21New1.add(card3.get(i)); } }else { for (int i = 0; i < 7; i++) { list21New1.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New1.add(card3.get(i)); } for (int i = 0; i < 7; i++) { list21New1.add(card2.get(i)); } } card1.clear(); card2.clear(); card3.clear(); for (int i = 0; i < 21; i++) { card1.add(list21New1.get(i)); i++; card2.add(list21New1.get(i)); i++; card3.add(list21New1.get(i)); } System.out.println("第1疊:"+card1); System.out.println("第2疊:"+card2); System.out.println("第3疊:"+card3); //判斷輸入 try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } Scanner scanner3 = new Scanner(System.in); System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數字1;如果在第2疊請輸入數字2;如果在第3疊請輸入數字3"); System.out.println("請輸入:"); int b = scanner3.nextInt(); //新建3個數組,分3次重新存重新按指定規則排序的21張牌 ArrayList<String> list21New2 = new ArrayList<>(); if (b==1){ for (int i = 0; i < 7; i++) { list21New2.add(card2.get(i)); } for (int i = 0; i < 7; i++) { list21New2.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New2.add(card3.get(i)); } }else if (b==2){ for (int i = 0; i < 7; i++) { list21New2.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New2.add(card2.get(i)); } for (int i = 0; i < 7; i++) { list21New2.add(card3.get(i)); } }else { for (int i = 0; i < 7; i++) { list21New2.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New2.add(card3.get(i)); } for (int i = 0; i < 7; i++) { list21New2.add(card2.get(i)); } } card1.clear(); card2.clear(); card3.clear(); for (int i = 0; i < 21; i++) { card1.add(list21New2.get(i)); i++; card2.add(list21New2.get(i)); i++; card3.add(list21New2.get(i)); } System.out.println("第1疊:"+card1); System.out.println("第2疊:"+card2); System.out.println("第3疊:"+card3); //判斷輸入 try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } Scanner scanner4 = new Scanner(System.in); System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數字1;如果在第2疊請輸入數字2;如果在第3疊請輸入數字3"); System.out.println("請輸入:"); //新建3個數組,分3次重新存重新按指定規則排序的21張牌 ArrayList<String> list21New3 = new ArrayList<>(); int c = scanner2.nextInt(); if (c==1){ for (int i = 0; i < 7; i++) { list21New3.add(card2.get(i)); } for (int i = 0; i < 7; i++) { list21New3.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New3.add(card3.get(i)); } }else if (c==2){ for (int i = 0; i < 7; i++) { list21New3.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New3.add(card2.get(i)); } for (int i = 0; i < 7; i++) { list21New3.add(card3.get(i)); } }else { for (int i = 0; i < 7; i++) { list21New3.add(card1.get(i)); } for (int i = 0; i < 7; i++) { list21New3.add(card3.get(i)); } for (int i = 0; i < 7; i++) { list21New3.add(card2.get(i)); } } System.out.println("好瞭,稍等片刻!讓我猜猜你記住的是什麼牌......"); try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } System.out.println("真相永遠隻有一個,你選的牌是"+list21New3.get(10)+"!"); System.out.println("什麼?你說我是運氣好?不!這是“魔法”!"); } }
運行結果
其中一次運行結果:開始我記住的就是梅花K!
魔術表演步驟
值得一提的是,將21張撲克牌分成3組的具體操作,應該是:
將21張撲克牌拿在手上,按順序,從左到右依次發牌,每發3次算一輪,一共發七輪,發完就會產生3疊牌,每疊7張!
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