Java基礎之FastJson詳解

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一、fastJson將json格式字符串轉化成List集合

註：json格式字符串必須符合數組型格式如[{“a”:a},{“b”:b}]

場景一：前端向後臺傳遞數組格式的json字符串，如何轉化成List集合

List<AccountBean> readJson2List =JSON.parseArray(json, AccountBean.class)註意這裡是Bean.class而不是List.class

	@Test
	public void readJson2ListBean() {
		String json = "[{\"address\": \"address2\",\"name\":\"haha2\",\"id\":2,\"email\":\"email2\"},{\"address\":\"address\",\"name\":\"haha\",\"id\":1,\"email\":\"email\"}]";
		List<AccountBean> readJson2List =JSON.parseArray(json, AccountBean.class);
		//輸出測試
		JsonUtils.beanToJson(readJson2List);
	}

場景二：前端向後臺傳遞數組格式的json字符串，如何轉化成List<HashMap<String,Object>>集合

	@Test
	public void readJson2ListMap() {
		String json = "[{\"address\": \"address2\",\"name\":\"haha2\",\"id\":2,\"email\":\"email2\"},{\"address\":\"address\",\"name\":\"haha\",\"id\":1,\"email\":\"email\"}]";
		List<HashMap> readJson2List =JSON.parseArray(json,HashMap.class);
		//輸出測試
		JsonUtils.beanToJson(readJson2List);
	}

二、fastJson將json格式字符串轉化成對象

場景一：前端向後臺傳遞數組格式的json字符轉化成Bean對象

@Test
	public void readJson2Bean() {
		String json = "{\"address\": \"address2\",\"name\":\"haha2\",\"id\":2,\"email\":\"email2\"}";
		AccountBean accountBean  =JSON.parseObject(json,AccountBean.class);
		//輸出測試
		JsonUtils.beanToJson(accountBean);
	}

場景二：前端向後臺傳遞數組格式的json字符串Map<String,Object>集合

@Test
	public void readJson2Map() {
		String json = "{\"address\": \"address2\",\"name\":\"haha2\",\"id\":2,\"email\":\"email2\"}";
		HashMap<String,Object> accountBean  =JSON.parseObject(json,Map.class);
		//輸出測試
		JsonUtils.beanToJson(accountBean);
	}

測試：

三、FastJson將對象或集合轉化成json格式字符串

@Test
	public void beanAndCollectionTOJson() {
		AccountBean	bean = new AccountBean();
		bean.setAddress("china-Guangzhou");
		bean.setEmail("[email protected]");
		bean.setId(1);
		bean.setName("hoojo");
		String json  = JSON.toJSONString(bean);
		System.out.println(json);
	}

四、FastJson將json格式字符串轉化成json對象

@Test
	public void jsonStringTOJsonBean() {
		String json = "{\"address\": \"address2\",\"name\":\"haha2\",\"id\":2,\"email\":\"email2\"}";
		JSONObject parse = (JSONObject) JSON.parse(json);
		String address = (String) parse.get("address");
		System.out.println("輸出address=="+address);
	}

五、FastJson將json格式字符串轉化成json數組

	@Test
	public void jsonString2JsonArray() {
		String json = "[{\"address\": \"address2\",\"name\":\"haha2\",\"id\":2,\"email\":\"email2\"},{\"address\":\"address\",\"name\":\"haha\",\"id\":1,\"email\":\"email\"}]";
		JSONArray parseArray = JSON.parseArray(json);
		//輸出測試
		JsonUtils.beanToJson(parseArray.get(0));
	}

六、FastJson將java對象轉化成json對象

@Test
	public void beanAndCollectionTOJsonBean() {
		AccountBean	bean = new AccountBean();
		bean.setAddress("china-Guangzhou");
		bean.setEmail("[email protected]");
		bean.setId(1);
		bean.setName("hoojo");
		JSONObject json  = (JSONObject) JSON.toJSON(bean);
		json.get("address");
		System.out.println(json);
	}

到此這篇關於Java基礎之FastJson詳解的文章就介紹到這瞭,更多相關Java FastJson內容請搜索WalkonNet以前的文章或繼續瀏覽下面的相關文章希望大傢以後多多支持WalkonNet！

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