PostgreSQL 查找當前數據庫的所有表操作

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實現的功能類似MySQL：

show tables;

在 PostgreSQL 中需要寫：

select * from pg_tables where schemaname = ‘public’;

返回結果類似如下：

schemaname | tablename | tableowner | tablespace | hasindexes | hasrules | hastriggers | rowsecurity 
------------+-----------+------------+------------+------------+----------+-------------+-------------
 public  | deploy | postgres |   | t   | f  | f   | f
 public  | deploy2 | postgres |   | f   | f  | f   | f
(2 rows)

補充：PostgreSql 獲取所有的表、視圖、字段、 主鍵

PostgreSQL獲取數據庫中所有view名 視圖：

SELECT viewname FROM pg_views 
WHERE  schemaname ='public'

postgreSQL獲取數據庫中所有table名 表：

SELECT tablename FROM pg_tables 
WHERE tablename NOT LIKE 'pg%' 
AND tablename NOT LIKE 'sql_%'
ORDER BY tablename;

postgreSQL獲取某個表tablename 所有字段名稱 ， 類型，備註,是否為空 等

SELECT col_description(a.attrelid,a.attnum) as comment,pg_type.typname as typename,a.attname as name, a.attnotnull as notnull
FROM pg_class as c,pg_attribute as a inner join pg_type on pg_type.oid = a.atttypid
where c.relname = 'tablename' and a.attrelid = c.oid and a.attnum>0

postgreSQL獲取某個表tablename 的主鍵信息

select pg_attribute.attname as colname,pg_type.typname as typename,pg_constraint.conname as pk_name from 
pg_constraint inner join pg_class 
on pg_constraint.conrelid = pg_class.oid 
inner join pg_attribute on pg_attribute.attrelid = pg_class.oid 
and pg_attribute.attnum = pg_constraint.conkey[1]
inner join pg_type on pg_type.oid = pg_attribute.atttypid
where pg_class.relname = 'tablename' 
and pg_constraint.contype='p'

以上為個人經驗，希望能給大傢一個參考，也希望大傢多多支持WalkonNet。如有錯誤或未考慮完全的地方，望不吝賜教。

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