Python統計節假日剩餘天數的腳本

1、前言

如何快速的想瞭解距離節假日還有多少天?

接下來使用Python腳本來解決這個問題。

2、倒計時腳本

腳本代碼:

#!/usr/bin/env python
# -*- coding: utf-8 -*-
 
from colorama import init, Fore
from zhdate import ZhDate
import datetime
def get_week_day(date):
    week_day_dict = {
        0: '星期一',
        1: '星期二',
        2: '星期三',
        3: '星期四',
        4: '星期五',
        5: '星期六',
        6: '星期天',
    }
    day = date.weekday()
    return week_day_dict[day]
def time_parse(today):
    distance_year = (datetime.datetime.strptime(f"{today.year}-01-01", "%Y-%m-%d").date() - today).days
    distance_year = distance_year if distance_year > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-01-01", "%Y-%m-%d").date() - today).days
    distance_big_year = (ZhDate(today.year, 1, 1).to_datetime().date() - today).days
    distance_big_year = distance_big_year if distance_big_year > 0 else (
            ZhDate(today.year + 1, 1, 1).to_datetime().date() - today).days
    distance_4_5 = (datetime.datetime.strptime(f"{today.year}-04-05", "%Y-%m-%d").date() - today).days
    distance_4_5 = distance_4_5 if distance_4_5 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-04-05", "%Y-%m-%d").date() - today).days
    distance_5_1 = (datetime.datetime.strptime(f"{today.year}-05-01", "%Y-%m-%d").date() - today).days
    distance_5_1 = distance_5_1 if distance_5_1 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-05-01", "%Y-%m-%d").date() - today).days
    distance_5_5 = (ZhDate(today.year, 5, 5).to_datetime().date() - today).days
    distance_5_5 = distance_5_5 if distance_5_5 > 0 else (
            ZhDate(today.year + 1, 5, 5).to_datetime().date() - today).days
    distance_8_15 = (ZhDate(today.year, 8, 15).to_datetime().date() - today).days
    distance_8_15 = distance_8_15 if distance_8_15 > 0 else (
            ZhDate(today.year + 1, 8, 15).to_datetime().date() - today).days
    distance_10_1 = (datetime.datetime.strptime(f"{today.year}-10-01", "%Y-%m-%d").date() - today).days
    distance_10_1 = distance_10_1 if distance_10_1 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-10-01", "%Y-%m-%d").date() - today).days
    # print("距離周末: ", 5 - today.weekday())
    # print("距離元旦: ", distance_year)
    # print("距離大年: ", distance_big_year)
    # print("距離清明: ", distance_4_5)
    # print("距離勞動: ", distance_5_1)
    # print("距離端午: ", distance_5_5)
    # print("距離中秋: ", distance_8_15)
    # print("距離國慶: ", distance_10_1)
    time_ = [
        {"v_": 5 - 1 - today.weekday(), "title": "周末"}, # 距離周末
        {"v_": distance_year, "title": "元旦"}, # 距離元旦
        {"v_": distance_big_year, "title": "過年"}, # 距離過年
        {"v_": distance_4_5, "title": "清明節"}, # 距離清明
        {"v_": distance_5_1, "title": "勞動節"}, # 距離勞動
        {"v_": distance_5_5, "title": "端午節"}, # 距離端午
        {"v_": distance_8_15, "title": "中秋節"}, # 距離中秋
        {"v_": distance_10_1, "title": "國慶節"}, # 距離國慶
    ]
    time_ = sorted(time_, key=lambda x: x['v_'], reverse=False)
    return time_
def countdown():
    init(autoreset=True)
    today = datetime.date.today()
    now_ = f"{today.year}年{today.month}月{today.day}日"
    week_day_ = get_week_day(today)
    print(f'\n\t\t {Fore.GREEN}{now_} {week_day_}')
    str_ = '''
         開始!
    '''
    print(f'{Fore.RED}{str_}')
    time_ = time_parse(today)
    for t_ in time_:
        print(f'\t\t {Fore.RED}距離{t_.get("title")}還有: {t_.get("v_")}天')
    tips_ = '''
         結束!
    print(f'{Fore.RED}{tips_}')
    print(f'\t\t{Fore.CYAN} 公眾號:AllTests軟件測試\n')
if __name__ == '__main__':
    countdown()

在PyCharm上執行結果:

在終端上執行結果:

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