C語言實現雙人五子棋遊戲

本文實例為大傢分享瞭C語言實現雙人五子棋遊戲的具體代碼,供大傢參考,具體內容如下

實現功能

生成棋盤玩傢1與玩傢2對戰,哪個玩傢率先有連續5子連線,哪個玩傢贏。

如何實現

組成:

二維數組:board[ROW][COL],定義一個ROW*COL的棋盤。

主要邏輯:

顯示棋盤,提示用戶下子,下子後判斷

1.顯示棋盤很簡單,慢慢湊棋盤就好
2. 用戶下子,註意兩個條件:棋子在棋盤裡,下子位置未被占用。
3.判斷是最難的,

方法:從下子位置的8個方向(上,下,左,右,右上,右下,左上,左下)計算相同棋子數目,然後將對角的棋子數相加,等於5說明有5子連線

主要函數中用到三個主要實現函數:

Showboard(board, ROW, COL);//展示棋盤
Playermove(board, ROW, COL, cur);//玩傢下註,cur表示哪個玩傢下子
Judge(board, ROW, COL);//判斷5子連線
Getcount(board[][COL], row, col, dir)//計算方向dir相同棋子數

代碼

頭文件

#ifndef __FIVECHREE_H__
#define __FIVECHEE_H__


#include<stdio.h>
#include<windows.h>
#pragma warning(disable:4996)

#define ROW 10//棋盤行數
#define COL 10//棋盤列數
#define INIT '*'//棋盤初始化

#define PLAYER1 1
#define PLAYER2 2
#define NEXT 3//繼續往下下
#define DRAW 4//棋盤下滿 平局

//8個方向
#define UP 10
#define RIGHT_UP 11
#define RIGHT 12
#define RIGHT_DOWN 13
#define DOWN 14
#define LEFT_DOWN 15
#define LEFT 16
#define LEFT_UP 17

extern void Menu();
extern void Game();

#endif

main函數源文件

#include"fivechree.h"
int main(){
 int quit = 0;
 while (!quit){
  Menu();
  int select = 0;
  scanf("%d", &select);
  switch (select){
  case 1:
   Game();
   break;
  case 2:
   quit = 1;
   break;
  default:
   printf("Enter Error!\n");
   break;
   
  }

 }
 printf("Byebye\n");
 system("pause");
 return 0;
}

函數定義源文件

#include"fivechree.h"

static int x = 0;
static int y = 0;

void Menu(){
 printf("+---------------------+\n");
 printf("+- 1.Play    2.Exit  -+\n");
 printf("+---------------------+\n");
 printf("Please Enter Your Select#");

}
static void Showboard(int board[][COL], int row, int col){//展示棋盤 o玩傢1棋子,x玩傢2棋子
 system("cls");
 for (int i = 0; i < row; i++){
  for (int j = 0; j < col; j++){
   switch (board[i][j]){
   case PLAYER1:
    board[i][j] = 'o';
    break;
   case PLAYER2:
    board[i][j] = 'x';
    break;
   case 0:
    board[i][j] = INIT;
    break;
   default:
    break;
   }
  }
 }
 printf("  ");
 for (int i =1; i <= row; i++){
  printf("%2d ", i);
 }
 printf("\n");
 for (int i = 1; i <= row; i++){
  printf("%-2d", i);
  for (int j = 1; j <= col; j++){
   printf(" %c ", board[i - 1][j - 1]);
  }
  printf("\n");
 }
}

static void Playermove(int board[][COL], int row, int col, int who){//玩傢下子,who 為哪個玩傢下子
 while (1){
  printf("Please Enter PLAYER%d Postion<x,y>#", who);
  scanf("%d %d", &x, &y);
  if (x<1 || x>row || y<1 || y>col){  //超過棋盤范圍
   printf("Postion is error!\n");
   continue;
  }
  if (board[x - 1][y - 1] == INIT){//判斷位置是否已被下子
   board[x - 1][y - 1] = who;
   break;
  }
  printf("Postion is not empty\n");
 }

}

static int Getcount(int board[][COL], int row, int col, int dir){//判斷8個方向相同棋子的數目
 int _x = x;//_x,_y變化,後面與x,y棋子相比較
 int _y = y;
 int count = 0;
 while (1){
  switch (dir){
  case UP:
   _x--;
   break;
  case DOWN:
   _x++;
   break;
  case LEFT:
   _y--;
   break;
  case RIGHT:
   _y++;
   break;
  case RIGHT_UP:
   _x--, _y++;
   break;
  case RIGHT_DOWN:
   _x++, _y++;
   break;
  case LEFT_DOWN:
   _x++, _y--;
   break;
  case LEFT_UP:
   _x--, _y--;
   break;
  default:
   break;
  }
  if (_x>=1 || _x<=row || _y>=1 || _y<=col){//棋子不能越界
   if (board[x-1][y-1] == board[_x-1][_y-1]){
    //printf("yes\n");
    count++;
   }
   else{
    //printf("no\n");
    break;
   }
  }
  else{
   return count;
  }
  
 }
 return count;
}
//如何判斷:從下子位置的8個方向(上,下,左,右,右上,右下,左上,左下)
//計算相同棋子數目,然後將對角的棋子數相加,等於5說明有5子連線
static int Judge(int board[][COL], int row, int col){
 int count1 = Getcount(board, row, col, UP)\
  + Getcount(board, row, col, DOWN);
 //printf("%d\n", count1);
 if (count1 >= 4){
  return board[x-1][y-1];
 }
 count1 = Getcount(board, row, col, RIGHT_UP)\
  + Getcount(board, row, col, LEFT_DOWN);
 //printf("%d\n", count1);
 if (count1 >= 4){
  return board[x-1][y-1];
 }
 count1 = Getcount(board, row, col, RIGHT)\
  + Getcount(board, row, col, LEFT);
 //printf("%d\n", count1);
 if (count1 >= 4){
  return board[x-1][y-1];
 }
 count1 = Getcount(board, row, col, RIGHT_DOWN)\
  + Getcount(board, row, col, LEFT_UP);
 if (count1 >= 4){
  return board[x-1][y-1];
 }

 for (int i = 0; i < row; i++){//判斷棋盤是否下滿
  for (int j = 0; j < col; j++){
   if (board[i][j] == INIT){
    return NEXT;
   }
  }
 }
 return DRAW;
}


void Game(){
 int board[ROW][COL] = { 0 };
 //memset(board, INIT, ROW*COL);
 int result = 0;
 int cur = PLAYER1;
 Showboard(board, ROW, COL);//先展示棋盤
 while (1){
  //Showboard(board, ROW, COL);
  Playermove(board, ROW, COL, cur);
  Showboard(board, ROW, COL);//棋盤將board數組變化,所以要在判斷前將數組變化
  result = Judge(board, ROW, COL);
  if (result != NEXT){
   break;
  }
  cur = (cur == PLAYER1 ? PLAYER2 : PLAYER1);//三目表達式,註意不是 PLAYER1 ? PLAYER2 : PLAYER1
 }

 Showboard(board, ROW, COL);
 switch (result){
 case 'o':
  printf("Player1 Win!\n");
  break;
 case 'x':
  printf("Player2 Win!\n");
  break;
 case DRAW:
  printf("Tie Game!\n");
  break;
 default:
  //printf("%c\n", result);
  printf("BUG\n");
  break;
 }
}

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